The combinational logic circuit is defined as a combination of logic devices . The output of a Combinational logic circuit is a function o...
f(A,B,C)=AB+C
X̄= AB̄C+ABC̄ = A(B̄C+BC̄)
= A(B⊕C)
Block diagram
Design with 3 inputs
A, B, C, and the condition are when any output will be low only when A is high while B and C are different.
Solution:
A is high that means A = 1.
B and C are different means when B =0 then C =1 and when B= 1 then C =0.
Here inputs are 3 . So, combinations = 2³ =8
A | B | C | x |
0 | 0 | 0 | 1 |
0 | 0 | 1 | 1 |
0 | 1 | 0 | 1 |
0 | 1 | 1 | 1 |
1 | 0 | 0 | 1 |
1 | 0 | 1 | 0 |
1 | 1 | 0 | 0 |
1 | 1 | 1 | 1 |
Here A = 0 in first 4 entries. So, the value of X will be 1 because it not satisfying the condition A =1 (A is low in this case).
In the next two rows, it is satisfying both of the conditions. A is high (A=1) and B and C are different. That is why we got X =0.
In the final two rows A =1. But the value of B and C are equal. So, these are not fulfilling the conditions.
Equation if inputs are not satisfying the conditions
X = ĀB̄C̄+ĀB̄C+ĀBC̄+ĀBC+ABC̄+ABC
= ĀB̄(C+C̄)+ĀB(C̄+C)+AB(C̄+C)
= ĀB̄+ĀB+AB [C̄+C=1]
= AB+ĀB̄+ĀB
= (A⊕B)+ĀB
Equation if inputs are satisfying the conditions




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